regex - AWK: Using a variable as part of a regular expression -


this question has answer here:

i have text file similar 1 containing username, description , 2 time range values german date format:

user###@###description###@###1. august - 8. august 2016###@###1. september - 7. september 2016

each field gets separated using ###@### delimiter. check if field (e.g. $3) contains 2 identical month names. if there 2 month names in specified field, first month name should removed, output of awk is:

user###@###description###@###1. - 8. august 2016###@###1. - 7. september 2016

then got idea create for-loop bash script (with awk commands), increments i in order read out month name predefined variable. here can more detailed

script.sh:

m1=january; m2=february; m3=march; m4=april; m5=may; m6=june; m7=july; m8=august; m9=september; m10=october; m11=november; m12=december       awk -f '###@###' '     {for (i=1;i++;i<=12){      count=0;     $3 ~ 'm'i {count++};     if (count == 2){gsub(mi,"" ,$3)}     }}' info.txt > info.tmp

unfortunately unable search varname mi (like m1, m2, m3.. etc.)

what have change in order search variable pattern actions?

you can put predefined names in awk script. this, maybe. (quick hack - log off day ;) )

awk -f ... ' begin { m[1]="january"; m[2]="february"; ... }              {for(i=1...              if ( $3 ~ m[i] ) { count++ }              ...}'

edit: benefit of future readers, here's text op's shorttext.com link below:

awk -f '###@###' ' begin{m1="januar"; m2="february"; m3="march"; m4=april; m5=may; m6=june; m7=july; m8=august; m9=september; m10=october; m11=november; m12=december} {for (i in m){ count=0; $3 ~ (m[i] ".*" m[i]) {print ++count}; if (count == 1){sub(m[i],"" ,$3)} }}' info.txt > info.tmp


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