replace <br> with <br/ > in XSLT 2.0 -

the question asked many times, not find help.

i replace

<br> 

to

<br /> 

in nodes.

xml

<paragraphs>    <paragraph><![cdata[lorem ipsum dolor sit amet, consetetur sadipscing elitr.<br>sed diam nonumy eirmod tempor invidunt ut labore et dolore magna aliquyam erat.<br>sed diam voluptua.<br>at vero eos et accusam et justo duo dolores et ea rebum.]]>    </paragraph> <paragraphs> 

xsl

<xsl:template match="paragraph">    <paragraph>      <xsl:attribute name="type">public</xsl:attribute>      <xsl:value-of select="replace(., '\<br\>', '\<br /\>')"/>    </paragraph> </xsl:template> 

unfortunately saxon quits with

sxxp0003: error reported xml parser: value of attribute "select"    associated element type "null" must not contain '<' character. org.xml.sax.saxparseexception: value of attribute "select" associated element type "null" must not contain '<' character. 

i tried escaping "\" nevertheless can''t right.

any ideas?

try way:

<xsl:template match="paragraph">     <paragraph type="public">         <xsl:value-of select="replace(., '&lt;br>', '&lt;br/>')"/>     </paragraph> </xsl:template> 

---

demo: http://xsltransform.net/gweamku