regex - Rexex Everything after the "." but ignore "|" -


i have 2 variations of text string:

10.09.2016 | 45 min. | swr fernsehen | ut

or

07.09.2016 | 57 min. wdr fernsehen

i looking end with:

swr fernsehen | ut

and

wdr fernsehen

this have tried capturing group:

\\.\s(.*)

this returns:

| swr fernsehen | ut wdr fernsehen

i cant work out how " take after "." ignore "|"

any ideas?

you may use following regular expression:

.*\.(?:\s*\|)?\s*(.*)

see regex demo

the .*\. match , including last . (because * greedy quantifier), (?:\s*\|)? match 1 or 0 sequences of 0+ whitespaces + |, \s* - 0 or more whitespaces , (.*) grab rest group 1, access group contents tool/language features.


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