Python Pandas group by function -


i have table 

    uname   sid usage 0   ahmad     5 1   ahmad     7 2   ahmad     10 3   ahmad   b   2 4   mohamad c   6 5   mohamad c   7 6   mohamad c   9

i want group uname , side, , have usage column = group.max - group.min. if group count 1 return group max

the out put should 

    uname   sid usage 0   ahmad     5 1   ahmad   b   2 2   mohamad c   3

first, use agg grab min, max, , size of each group.
multiply min size > 1. when is, equal min, else 0. subtract max.

d1 = df.groupby(['uname', 'sid']).usage.agg(['min', 'max', 'size']) d1['max'].sub(d1['min'].mul(d1['size'].gt(1))).reset_index(name='usage')

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